Rules and how to solve YajiLin.
Rules
  1. The cell with the arrow and the number is the question cell, and the number represents the number of black cells that enter the direction of the arrow from that position.
  2. The black cell do not line up vertically and horizontally, and the black cell do not divide the board. The cell next to the black cell is always the problem cell or white cell.
  3. Cell that are neither black nor problem cell (white cell) always pass through a line that passes through the center and goes straight to the side. Line segments can bend at the center of the cell but cannot branch, cross, or break.
  4. The line segment eventually becomes a loop.There are not multi loops or breaks.
  5. A place that has nothing to do with the specification in the problem may be a black cell.


jump to YajiLin problem.
Tips for solving
解くポイントはまず問題で指定された黒枡がぴたりと入るところが無いか探します。黒枡が決まればその周りは白枡になり必ず線分が通りますので マークをつけておくとよいでしょう。
ある枡の隣枡3か所が黒枡や盤面の端で行きどまりならその枡は黒枡になります。またある桝を黒枡にすると隣の枡が線分の袋小路になってしまう場合にはその枡は黒枡にできません。
線分を引ける方向が二つしかない白桝はその方向に線分が引かれます。
線分を引く時には小さなループが出来ないように引いて行くことも必要です。
それでは例題で説明します。
ここでの説明では黒枡になるか線分が通るか未定の枡は灰色で、線分が通っていたり 通ると決まった枡は白で表示しています。 印刷されたパズルを解く時には線分が通ると決まった枡には 中点(・)をつけておくのも良いでしょう。
The point to solve is to first find if there is any place where the black cell specified in the problem can enter. Once the black cell is determined, the area around it will be a white cell and the line will always pass. You may want to add a mark.
If three places next to a certain cell stop at a black cell or the edge of the board, the cell will be a black cell. In addition, if a certain cell becomes a black cell, if the next square becomes a dead-end of a line, that cell cannot be a black cell.
A white cell that has only two directions to draw a line is drawn in that direction.
When drawing a line segment, it is necessary to draw it so that a small loop cannot be formed.
Let me explain with an example.
In the explanation here, cells that are undetermined whether they will be black or pass through the line are gray, and cells that have passed or decided to pass a line are displayed in white. When solving printed puzzles, it is a good idea to add a midpoint (・) to the square that has been determined to pass the line cell.
The following figure is the problem. The cell with the number with the arrow is the problem cell. ex0
First, notice the 2 with the left arrow near the center. This means that two of the three light green cells on the left side of this cell are black cells. There are no two black cascades, so the two green framed both end cells are black cell.Just entered.
The light blue cell in the upper right corner is a dead end, so it is a black cell.
Also, pay attention to the yellow cell, and when this cell becomes a black cell, the next pink cell becomes a white cell. And since it will be a dead end that can only draw broken lines. So this yellow cell must be a white cell.
ex1
The white and black cell determined up to this point are shown in the following figure, here, the cell around the fixed black cell is also a white cell.
Looking at the area around the black cell here, some of the four sides around the white cell can draw line segments in only two directions. The line segments of these cells. You can confirm in the direction that you can draw.
ex2
The line segment has been confirmed.
Since the line segment was drawn here, the line segment can be drawn in two directions even for the white cells above and below the black cell near the center, so the line segment can be confirmed.
ex3
he line segment has been confirmed.
Let's consider the top cell here. On the left side of 2 with the left arrow, there are only two space to be black left, so these two are determined as black cells.
ex4
There is a cell where the line segment can be determined again around the black cell. Considering the column on the right, there is a problem cell at the bottom, and there is a black cell above this cell. But the top cell is already a black cell, so the remaining cells are white cells. ex5
In the rightmost column, there is already one black square, so the top of the bottom problem square 1 is now a white cell. But if the left side of this problem cell 1 is not a white cell, the line segment will be cut off at the left white cell and it will become a dead end.
This extends the place where the line segment can be determined.
When you come to the next figure, you have a break. The following correct answer can be obtained considering that the two black mas are not lined up and that the line segments are one loop without interruption.
ex6
This is the correct solution. ex7
Next, I will introduce the pattern that determines some black cells, white cells, and line segments. It's a good idea to consider why this happens.
If the second cell in both the vertical and horizontal directions from the edge of the board is a problem cell and the cell at the end of the board (vertical and horizontal diagonal) is not a problem cell, the line segment is determined so that it turns around the green cell as shown in the following figure.
In addition, if a black cell is used as a cell that is obliquely located from the end of the line, as in the cell shown in the green frame in the figure, it will be a white cell when the line segment branches off. (There are others in the figure.)
Except for the edge of the board, the black cell is exactly the specified number when it enters every other black cell, like the blue 2 on the lower left. But if there is no other black or problem cell at the edge of the table, such as blue 3 on the right side of the board, every third cell is black lined up.
In addition, when the number of black cell in the same direction is specified in the specified direction, such as red 2, the number of black cell may be exactly the specified number between the two problem cells considering the difference.
ex10
See the following figure. Here, the black cell is determined by the two problem cell 2 and the line segment is drawn several places. Here, let's consider whether the line drawn from below on the blue cell is drawn next upward or leftward.
Considering the line segment drawn from the outside in the light blue area, it is two blue lines. So, if you draw upward at the position of the blue framed cell, a total of three line segments will be drawn outside from the light blue area. If an odd number is drawn, line segments will be interrupted or branched in this area, violating the rules. Therefore, a line segment is drawn to the left at the position of the blue frame.
There are many other ways to do this.
ex11



2020.2.28 Modified
2010.6.12 First edition
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